0=-12-1x-1x^2

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Solution for 0=-12-1x-1x^2 equation:


Simplifying
0 = -12 + -1x + -1x2

Solving
0 = -12 + -1x + -1x2

Solving for variable 'x'.

Combine like terms: 0 + 12 = 12
12 + x + x2 = -12 + -1x + -1x2 + 12 + x + x2

Reorder the terms:
12 + x + x2 = -12 + 12 + -1x + x + -1x2 + x2

Combine like terms: -12 + 12 = 0
12 + x + x2 = 0 + -1x + x + -1x2 + x2
12 + x + x2 = -1x + x + -1x2 + x2

Combine like terms: -1x + x = 0
12 + x + x2 = 0 + -1x2 + x2
12 + x + x2 = -1x2 + x2

Combine like terms: -1x2 + x2 = 0
12 + x + x2 = 0

Begin completing the square.

Move the constant term to the right:

Add '-12' to each side of the equation.
12 + x + -12 + x2 = 0 + -12

Reorder the terms:
12 + -12 + x + x2 = 0 + -12

Combine like terms: 12 + -12 = 0
0 + x + x2 = 0 + -12
x + x2 = 0 + -12

Combine like terms: 0 + -12 = -12
x + x2 = -12

The x term is x.  Take half its coefficient (0.5).
Square it (0.25) and add it to both sides.

Add '0.25' to each side of the equation.
x + 0.25 + x2 = -12 + 0.25

Reorder the terms:
0.25 + x + x2 = -12 + 0.25

Combine like terms: -12 + 0.25 = -11.75
0.25 + x + x2 = -11.75

Factor a perfect square on the left side:
(x + 0.5)(x + 0.5) = -11.75

Can't calculate square root of the right side.

The solution to this equation could not be determined.

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